Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 24

Answer

$3(x+4)-12ln|x+4|+C$

Work Step by Step

$\int \frac {3x}{x+4}dx$ $u=x+4; du=dx; x=u-4$ $\int \frac {3(u-4)} u du$ $3\int 1du-12\int \frac1 u du$ $3u-12ln|u|+C$ $3(x+4)-12ln|x+4|+C$
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