Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 23

Answer

$\frac 1 2 x^2+x+ln|x-1|+C$

Work Step by Step

$\int \frac {x^2}{x-1}dx$ $\int(x+1)dx+\int \frac 1 {x-1}dx$ $\frac 1 2 x^2+x+ln|x-1|+C$
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