Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 16

Answer

$- \frac{5}{2(t+6)^2}+C$

Work Step by Step

$\int \frac 5{(t+6)^3}dt$ $\int \frac 5{u^3}dt$ $5\int u^{-3}dt$ $5(\frac {u^{-2}}{-2})+C$ $-\frac 5{2u^2}+C$ $- \frac{5}{2(t+6)^2}+C$
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