Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 14

Answer

$\int \frac{du}{u\sqrt {u^2- a^2}}$ $u=x$ $a=2$

Work Step by Step

Try it: $u=x$ $du=dx$ $\int \frac{du}{u\sqrt {u^2- a^2}}=\frac 1 a arcscec \frac {|u|}{a} +C $ $\frac 1 2 arcsec \frac {|x|}2 +C$ $\int \frac{du}{u\sqrt {u^2- a^2}}$ $u=x$ $a=2$
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