Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 13

Answer

$\int e^u du$ $u=sinx$

Work Step by Step

Try it: $u=sinx$ $du=cosxdx$ $\int e^u du=e^u +C$ $e^{sinx} +C$ $\int e^u du$ $u=sinx$
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