Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 11

Answer

$\int sinudu$ $u=t^2$

Work Step by Step

Try it: $u=t^2$ $du=2tdt$ $\int sinudu=-cosu+C$ $\frac1 2 \int sin(t^2)2tdt$ $\frac1 2 \int sinudu$ $\frac 1 2 (-cosu+C)$ $\frac 1 2 (-cos(t^2)+C)$ $\frac 1 2 -cos(t^2)+C$ $\int sinudu$ $u=t^2$
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