Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.2 Exercises: 9

Answer

$$V=\frac{\pi}{4}$$

Work Step by Step

$V=\pi\int _0^1 (y^{\frac{3}{2}})^2 dy$ $V=\pi \int_0^1(y^3)dy$ $V=\pi[\frac{y^4}{4}]_0^1$ $V=\pi(\frac{1^4}{4}-\frac{0^4}{4})$ $V=\pi(\frac{1}{4}-0)$ $$V=\frac{\pi}{4}$$
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