Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.2 Exercises: 3

Answer

$$V=\frac{15}{2}\pi$$

Work Step by Step

r=$\sqrt x$ $V=\pi\int\limits_1^4(\sqrt x)^2 dx$ $V=\pi\int\limits_1^4(x)dx$ $V=\pi\frac{x^2}{2}│_1^4$ $V=\pi (\frac{4^2}{2}-\frac{1^2}{2})$ $V=\pi(\frac{16}{2}-\frac{1}{2})$ $V=\frac{15}{2}\pi$
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