Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - Review Exercises: 35

Answer

$y=Ce^{8x^{2}}$

Work Step by Step

$y'-16xy=0$ $\frac{dy}{dx}=16xy$ $\int \frac{1}{y}dy=\int 16xdx$ ln|y|=$8x^{2}+C_1$ $e^{8x^{2}+C_1}$=y $y=Ce^{8x^{2}}$
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