Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - Review Exercises: 5

Answer

y=$\frac{1}{2}$sin2x+C

Work Step by Step

dy=cos2xdx $\int$dy=$\int$cos2xdx $\int$dy=$\frac{1}{2}$$\int$cos2x(2)dx u=2x, du=2dx $\int$cosudu=sinu+C y=$\frac{1}{2}$sin2x+C
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