## Calculus 10th Edition

Published by Brooks Cole

# Chapter 6 - Differential Equations - Review Exercises: 5

#### Answer

y=$\frac{1}{2}$sin2x+C

#### Work Step by Step

dy=cos2xdx $\int$dy=$\int$cos2xdx $\int$dy=$\frac{1}{2}$$\int$cos2x(2)dx u=2x, du=2dx $\int$cosudu=sinu+C y=$\frac{1}{2}$sin2x+C

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.