Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - Review Exercises: 4

Answer

y=$\frac{3}{4}x^{4}-4x^{2}$+C

Work Step by Step

dy=$(3x^{3}-8x)$dx $\int$dy=$\int$$(3x^{3}-8x)$dx y=$3(\frac{x^{3+1}}{3+1})-8(\frac{x^{1+1}}{1+1}$)+C y=$\frac{3}{4}x^{4}-4x^{2}$+C
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