#### Answer

37.5 years

#### Work Step by Step

$P=Ce^{0.0185t}$
$2C=Ce^{0.0185t}$
$2=e^{0.0185t}$
$ln2=0.0185t$
$t=\frac{ln2}{0.0185}\approx 37.5 years$

Published by
Brooks Cole

ISBN 10:
1-28505-709-0

ISBN 13:
978-1-28505-709-5

37.5 years

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