Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - Review Exercises: 22


$y=k(50t - \frac{t^2}{2})+C$

Work Step by Step

$$\frac{dy}{dt} = k(50-t)$$ $$\int dy = \int k(50-t^1) dt$$ $$y=k(50t - \frac{t^{1+1}}{1+1})+C$$ $$y=k(50t - \frac{t^2}{2})+C$$
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