#### Answer

Yes it is a solution.

#### Work Step by Step

y=$x^{3}$, y'=$3x^{2}$
2xy'+4y=2x($3x^{2}$)+4($x^{3}$)=10($x^{3}$)

Published by
Brooks Cole

ISBN 10:
1-28505-709-0

ISBN 13:
978-1-28505-709-5

Yes it is a solution.

y=$x^{3}$, y'=$3x^{2}$
2xy'+4y=2x($3x^{2}$)+4($x^{3}$)=10($x^{3}$)

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