Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.4 Exercises: 13

Answer

$y=(x+C)e^{x^{3}}$

Work Step by Step

$y'-3x^{2}y=e^{x^{3}}$ Integrating factor: $e^{-\int 3e^{x^{2}}dx}=e^{-x^{3}}$ $ye^{-x^{3}}$=$\int$$e^{x^{3}}e^{-x^{3}}dx$=$\int$dx=$x+C$ $y=(x+C)e^{x^{3}}$
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