Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.3 Exercises: 14

Answer

$y=\sqrt{\frac{7}{6}e^x+C}$

Work Step by Step

$12yy'-7e^x=0$ $12yy'=7e^x$ $\int 12ydy=\int7e^xdx$ $12\frac{y^2}{2}=7e^x+C$ $y^2=\frac{7}{6}e^x+C$ $y=\sqrt{\frac{7}{6}e^x+C}$
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