Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.2 Exercises: 11

Answer

Q=-$\frac{k}{t}$+C

Work Step by Step

$\frac{dQ}{dt}=\frac{k}{t^{2}}$ $\int$$\frac{dQ}{dt}$=$\int$$\frac{k}{t^{2}}$dt $\int$dQ=-$\frac{k}{t}$+C Q=-$\frac{k}{t}$+C
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