Calculus 10th Edition

Published by Brooks Cole

Chapter 6 - Differential Equations - 6.2 Exercises: 11

Answer

Q=-$\frac{k}{t}$+C

Work Step by Step

$\frac{dQ}{dt}=\frac{k}{t^{2}}$ $\int$$\frac{dQ}{dt}=\int$$\frac{k}{t^{2}}$dt $\int$dQ=-$\frac{k}{t}$+C Q=-$\frac{k}{t}$+C

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.