## Calculus 10th Edition

Published by Brooks Cole

# Chapter 6 - Differential Equations - 6.2 Exercises: 11

#### Answer

Q=-$\frac{k}{t}$+C

#### Work Step by Step

$\frac{dQ}{dt}=\frac{k}{t^{2}}$ $\int$$\frac{dQ}{dt}=\int$$\frac{k}{t^{2}}$dt $\int$dQ=-$\frac{k}{t}$+C Q=-$\frac{k}{t}$+C

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