Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.1 Exercises: 27

Answer

No

Work Step by Step

$y=lnx, y'=\frac{1}{x} xy'-2y$ $\frac{1}{x} xy'-2$=$x(\frac{1}{x})-2lnx$ $x(\frac{1}{x})-2lnx$$\ne$$x^{3}e^{x}$
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