Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.1 Exercises: 23

Answer

Yes

Work Step by Step

$xy'-2y=x^{3}ex$ $y=x^{2}e^{x}, y'=x^{2}e^{x}+2e^{x}$ $y'=e^{x}(x^{2}+2x)$ $xy'-2y=x(e^{x}(x^{2}+2x))-2(x^{2}e^{x})$ $x(e^{x}(x^{2}+2x))-2(x^{2}e^{x})$=$x^{3}e^{x}$
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