## Calculus 10th Edition

$y=(-2 \ln 2)x-2 (\ln2 -1)$
$y=2^{-x}$ $y’=-\ln 2 (2^{-x})$ $y’(2) = \ln 2 (2^{-(-1)})$ $=-2 \ln 2$ $=14$ Equation of tangent: $y-2=-2 \ln 2(x+1)$ $y=(-2 \ln 2)x-2 (\ln2 -1)$