Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises: 43

Answer

$g'(t)=(2^t)(2t+t^2\ln 2)$

Work Step by Step

$g(t)=t^22^t$ $u=t^2$ $u’=2t$ $v=2^t$ $v’=(\ln 2)(3^t)$ $g’(t)=u’v+uv’$ $=(2t)(2^t)+(t^2)(\ln 2)(2^t)$ $=(2^t)(2t+t^2\ln 2)$
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