Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.3 Exercises: 7

Answer

$f(x)$ and $g(x)$ are inverse functions.

Work Step by Step

Let us find the inverse of $f(x)$ by solving for x. \[ y = \frac{1}{x} \\ \\ xy = 1 \\ \\ x = \frac{1}{y} \] We see that the inverse function of $f(x)$ is $\frac{1}{x}$ which is also $g(x)$. Therefore, $f(x)$ and $g(x)$ are inverse functions. Graphically, we see that every point on $f(x)$, when reflected over the line $g(x)$ lies on one point on $g(x)$. Specifically, if a point $(a,b)$ is on $f(x)$, then there is a point $(b,a)$ on $g(x)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.