Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.2 Exercises: 5

Answer

$\frac{1}{2}$$\ln| 2x+5|$ + C

Work Step by Step

$\int\frac{1}{2x+5} dx $ Let $u = 2x+5$ $\frac{du}{dx}$ = 2 $\frac{du}{2}$ = $dx$ Substitute $u$ and $dx$ into the original equation $\int\frac{1}{u}\frac{du}{2}$ = $\int\frac{1}{2}\frac{1}{u} du$ = $\frac{1}{2}$$\int\frac{1}{u} du$ = $\frac{1}{2}$$\ln|u|$ + C Since $u = 2x+5$, substituting it back will give you $\frac{1}{2}$$\ln| 2x+5|$ + C
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