Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.2 Exercises: 3

Answer

$\ln|x+1|$ + C

Work Step by Step

$\int\frac{1}{x+1} dx $ Let $u = x+1$ $\frac{du}{dx}$ = 1 $\frac{du}{1}$ = $dx$ Substitute $u$ and $dx$ into the original equation $\int\frac{1}{u}\frac{du}{1}$ = $\int\frac{1}{u} du$ = $\ln|u|$ + C Since $u = x+1$, substituting it back will give you $\ln|x+1|$ + C
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.