## Calculus 10th Edition

$\frac{x^{2}}{2} - 8\ln|x|$ + C
$\int\frac{x^{3}-8x}{x^{2}} dx$ = $\int(\frac{x^{3}}{x^{2}}-\frac{8x}{x^{2}} )dx$ = $\int(\frac{x}{1}-\frac{8}{x} )dx$ = $\int x dx -\int\frac{8}{x}dx$ = $\frac{x^{2}}{2} - 8\int\frac{1}{x}dx$ = $\frac{x^{2}}{2} - 8\ln|x|$ + C