Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.2 Exercises: 12

Answer

$\frac{x^{2}}{2} - 8\ln|x|$ + C

Work Step by Step

$\int\frac{x^{3}-8x}{x^{2}} dx $ = $\int(\frac{x^{3}}{x^{2}}-\frac{8x}{x^{2}} )dx$ = $\int(\frac{x}{1}-\frac{8}{x} )dx$ = $\int x dx -\int\frac{8}{x}dx$ = $\frac{x^{2}}{2} - 8\int\frac{1}{x}dx$ = $\frac{x^{2}}{2} - 8\ln|x|$ + C
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.