## Calculus 10th Edition

Rewrite: $\int x^{\frac{1}{3}}dx$ Integrate: $\int x^{\frac{1}{3}}=\dfrac{1}{\frac{1}{3}+1}\times x^{\frac{1}{3}+1}+C$ Simplify: $\int x^{\frac{1}{3}}=\dfrac{3x^{\frac{4}{3}}}{4}+C$
Rewrite the radical as a power. Integrate using the basic integration rules. Add and multiply out the numbers and add a constant $C.$