Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises: 23

Answer

$= x^{3} + \frac{1}{2}x^{2} - 2x +C $

Work Step by Step

$\int (x+1)(3x-2) dx$ $\int (x(3x-2)+1(3x-2))dx$ $\int (3x^{2} - 2x + 3x - 2) dx$ $\int (3x^{2} + x - 2) dx$ $= \frac{3x^{3}}{3} + \frac{x^{2}}{2} - 2x + C$ $= x^{3} + \frac{1}{2}x^{2} - 2x +C $
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