## Calculus 10th Edition

Published by Brooks Cole

# Chapter 3 - Applications of Differentiation - 3.5 Exercises: 25

#### Answer

$\lim\limits_{x \to -\infty}\frac{5x^2}{x+3} = -\infty$

#### Work Step by Step

We look at the terms with highest degree in the numerator and denominator, as these will be the only terms with any significance when x approaches infinity. $\lim\limits_{x \to -\infty}\frac{5x^2}{x+3} = \lim\limits_{x \to -\infty}\frac{5x^2}{x} = \lim\limits_{x \to -\infty}5x = -\infty$

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