Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - 3.5 Exercises: 25

Answer

$\lim\limits_{x \to -\infty}\frac{5x^2}{x+3} = -\infty$

Work Step by Step

We look at the terms with highest degree in the numerator and denominator, as these will be the only terms with any significance when x approaches infinity. $\lim\limits_{x \to -\infty}\frac{5x^2}{x+3} = \lim\limits_{x \to -\infty}\frac{5x^2}{x} = \lim\limits_{x \to -\infty}5x = -\infty$
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