Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - 3.5 Exercises: 21

Answer

$\lim\limits_{x \to \infty}\frac{2x-1}{3x+2} = \frac{2}{3}$

Work Step by Step

We look at the terms in the numerator and denominator with highest degree, as they will be the only terms with significance when x approaches infinity. $\lim\limits_{x \to \infty}\frac{2x-1}{3x+2} = \lim\limits_{x \to \infty}\frac{2x}{3x} = \lim\limits_{x \to \infty}\frac{2}{3} = \frac{2}{3}$
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