Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - 3.5 Exercises: 1

Answer

$f(x)$ is graph f

Work Step by Step

$f(x) = \frac{2x^2}{x^2+2} = \frac{2x^2 + 4 - 4}{x^2+2} = 2 - \frac{4}{x^2+2}$. $\frac{4}{x^2 + 2}$ never equals $0$ so $f(x)$ has a horizontal asymptote at $y = 2$. At $x=0$, $y = 0$ so that eliminates the options to c and f. At $x = -2$, $y$ is positive so this eliminates the options down to f.
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