## Calculus 10th Edition

Over the specified interval, the function has an absolute maximum equal to $1$ and an absolute minimum equal to $0.$
$y'=\frac{\pi}{8}\sec^2{\frac{\pi x}{8}}.$ $y'$ is not equal to $0$ or undefined over the specified interval$\to$ The function attains absolute extrema at the interval's boundaries. $y(0)=0.$ $y(2)=1.$ Over the specified interval, the function has an absolute maximum equal to $1$ and an absolute minimum equal to $0.$