Calculus 10th Edition

Published by Brooks Cole

Chapter 3 - Applications of Differentiation - 3.1 Exercises: 36

Answer

Over the specified interval, the function has an absolute maximum equal to $1$ and an absolute minimum equal to $0.$

Work Step by Step

$y'=\frac{\pi}{8}\sec^2{\frac{\pi x}{8}}.$ $y'$ is not equal to $0$ or undefined over the specified interval$\to$ The function attains absolute extrema at the interval's boundaries. $y(0)=0.$ $y(2)=1.$ Over the specified interval, the function has an absolute maximum equal to $1$ and an absolute minimum equal to $0.$

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