Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - 3.1 Exercises: 30

Answer

Over the specified interval, the function has an absolute maximum equal to $5$ and an absolute minimum equal to $0.$

Work Step by Step

Using the rule $\dfrac{d}{dx}|z(x)|=z'(x)\times\dfrac{|z(x)|}{z(x)}\to$ $g'(x)=\dfrac{|x+4|}{x+4}$ which is undefined for $x=-4.$ The interval's boundaries and $x=-4$ are possible candidates for absolute extrema. $g(-7)=3.$ $g(-4)=0.$ $g(1)=5.$ Over the specified interval, the function has an absolute maximum equal to $5$ and an absolute minimum equal to $0.$
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