## Calculus 10th Edition

The function has an absolute maximum equal to $24$ and an absolute minimum equal to $-8.$
$g'(x)=4x-8.$ $g'(x)=0\to x=2$ which is in the specified interval; hence, it is, along with the endpoints of the interval, a possible candidate for absolute extrema. $g(0)=0.$ $g(2)=-8.$ $g(6)=24.$ The function has an absolute maximum equal to $24$ and an absolute minimum equal to $-8.$