## Calculus 10th Edition

The absolute maximum is $5$ and the absolute minimum is $2$ over the specified interval
$f'(x)=\dfrac{3}{4}.$ Since $f'(x)$ is never equal to $0,$ and is defined for all x in the interval, the absolute extrema have to occur at the endpoints of the interval. $f(0)=2.$ $f(4)=5.$ The absolute maximum is $5$ and the absolute minimum is $2$ over the specified interval .