## Calculus 10th Edition

$f(x)$ has two critical numbers : {$0, 2$}
$f'(x)=3x^2-6x=3x(x-2).$ $f'(x)=0\to 3x(x-2)=0\to x=0$ or $x=2.$ $f(x)$ has two critical numbers : {$0, 2$}.