## Calculus 10th Edition

Since the function is not defined for $x=0$ and $x\approx6,$ it does not attain a relative or absolute minimum over the specified interval. The function has a critical number at 2, but attains neither a minimum nor a maximum there. The function has another critical number over the specified interval, which is $x\approx5.$ The function attains a relative and absolute maximum for $x\approx5.$