Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - Review Exercises: 50

Answer

$h''(t)=-10\cos{t}+15\sin{t}.$

Work Step by Step

$h'(t)=\dfrac{d}{dt}(10\cos{t})-\dfrac{d}{dt}(15\sin{t})=-10\sin{t}-15\cos{t}.$ $h''(t)=\dfrac{d}{dt}(-10\sin{t})+\dfrac{d}{dt}(-15\cos{t})=-10\cos{t}+15\sin{t}.$
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