## Calculus 10th Edition

$f''(x) = (\frac{225}{4})\sqrt x$
1. Find $f'(x)$ $f(x) = 15x^{\frac{5}{2}}$ $f'(x) = (15 \times \frac{5}{2})x^{(\frac{5}{2} - 1)}$ $f'(x) = (\frac{75}{2})x^{(\frac{3}{2})}$ 2. Find $f''(x)$ $f'(x) = (\frac{75}{2})x^{(\frac{3}{2})}$ $f''(x) = (\frac{75}{2} \times \frac{3}{2})x^{(\frac{3}{2}- 1)}$ $f''(x) = (\frac{225}{4})x^{\frac{1}{2}}$ $f''(x) = (\frac{225}{4})\sqrt x$