Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - Review Exercises: 30

Answer

$g'(x)=24x^3-24x^2+30x-20.$

Work Step by Step

Product Rule $(g’(x)=(u(x)(v(x))’=u’(x)v(x)+u(x)v’(x))$ $u(x)=2x^3+5x ;u’(x)=6x^2+5 $ $v(x)= 3x-4;v’(x)= 3$ $g'(x)=(6x^2+5)(3x-4)+(3)(2x^3+5x)$ $=24x^3-24x^2+30x-20.$
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