Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - Review Exercises: 23

Answer

The slope of the tangent at the point $(0, -8)$ is $0.$

Work Step by Step

$f'(x)=\dfrac{d}{dx}(2x^4)-\dfrac{d}{dx}(8)=8x^3.$ $f'(0)=8(0^3)=0.$
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