Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - Review Exercises: 20

Answer

$g'(\alpha)=\frac{5}{3}\cos{\alpha}-2.$

Work Step by Step

$g'(\alpha)=\dfrac{d}{d\alpha}(\frac{5}{3}\sin{\alpha})-\dfrac{d}{d\alpha}(2\alpha)\rightarrow$ $g'(\alpha)=\frac{5}{3}\cos{\alpha}-2.$
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