Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - Review Exercises: 14

Answer

$f'(x)=\dfrac{x+1}{2\sqrt{x^3}}.$

Work Step by Step

$\dfrac{d}{dx}(f(x))=\dfrac{d}{dx}(x^{\frac{1}{2}})-\dfrac{d}{dx}(x^{-\frac{1}{2}})\rightarrow$ $f'(x)=\frac{1}{2}(x^{-\frac{1}{2}})+\frac{1}{2}(x^{-\frac{3}{2}})=\dfrac{x+1}{2\sqrt{x^3}}.$
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