## Calculus 10th Edition

$\dfrac{dy}{dx}=2.$
$\dfrac{d}{dx}((4-x)y^2)=\dfrac{d}{dx}(x^3)\rightarrow$ $-y^2+\dfrac{dy}{dx}(2y(4-x))=3x^2\rightarrow$ $\dfrac{dy}{dx}=\dfrac{3x^2+y^2}{8y-2yx}.$ At $(2, 2)\rightarrow\dfrac{dy}{dx}=\dfrac{3(2)^2+2^2}{8(2)-2(2)(2)}=2.$