Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.5 Exercises: 3

Answer

$\dfrac{dy}{dx}=-\dfrac{\sqrt{y}}{\sqrt{x}}$

Work Step by Step

$\dfrac{d}{dx}(x^{\frac{1}{2}})+\dfrac{d}{dx}(y^{\frac{1}{2}})=\dfrac{d}{dx}(16)\rightarrow$ $\dfrac{1}{2\sqrt{x}}+\dfrac{dy}{dx}(\dfrac{1}{2\sqrt{y}})=0\rightarrow$ $\dfrac{dy}{dx}=-\dfrac{\sqrt{y}}{\sqrt{x}}.$
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