Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.5 Exercises: 22

Answer

$\frac{1}{3}$

Work Step by Step

$y^3-x^2=4$ $\frac{d}{dx}[y^3-x^2]=\frac{d}{dx}[4]$ $3y^2\frac{dy}{dx}-2x=0$ $\frac{dy}{dx}=\frac{2x}{3y^2}$ $(2,2)$ $\frac{2x}{3y^2}=\frac{2(2)}{3(2)^2}=\frac{4}{12}=\frac{1}{3}$
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