Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises: 126

Answer

False.

Work Step by Step

Correct solution: $u=\sin{2x}$; $\dfrac{du}{dx}=2\cos{2x}$ $\dfrac{d}{du}f(u)=2u$ $\dfrac{d}{dx}f(x)=\dfrac{d}{du}f(u)\times\dfrac{du}{dx}=4\cos{2x}\sin{2x}.$
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