Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises: 121

Answer

$h'(x)=\dfrac{x\cos{x}}{|x|}-|x|\sin{x}$

Work Step by Step

Product Rule: $(h’(x)=(u(x)(v(x))’=u’(x)v(x)+u(x)v’(x))$ $u(x)=|x| ;u’(x)=\dfrac{x}{|x|} $ $v(x)=\cos{x} ;v’(x)= -\sin{x}$ $h'(x)=\dfrac{x\cos{x}}{|x|}-|x|\sin{x}$ ; $x\ne0.$
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