Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises: 120

Answer

$f'(x)=\dfrac{2x^3-18x}{|x^2-9|}.$

Work Step by Step

$u=x^2-9$; $u'=2x$ $f'(x)=u'\dfrac{u}{|u|}=\dfrac{2x^3-18x}{|x^2-9|}.$
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