Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises: 91



Work Step by Step

$h'(x)=(3)(3)\frac{1}{9}(3x+1)^{3-1}=(3x+1)^2$ $h''(x)=(3)(2)(3x+1)^{2-1}=6(3x+1)=18x+6.$ $h''(1)=18(1)+6=24.$ A computer algebra system has been used to verify this result.
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