Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises: 87

Answer

$f''(x)=\dfrac{2}{(x-6)^3}$

Work Step by Step

$f(x)=(x-6)^{-1}$ $f'(x)=(1)(-1)(x-6)^{-1-1}=-\dfrac{1}{(x-6)^2}=-(x-6)^{-2}.$ $f''(x)=(-1)(-2)(x-6)^{-2-1}=\dfrac{2}{(x-6)^3}.$
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